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How can I programmatically tell if my code is running in a model or not?

Stacy Alme
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I want my code to behave differently while I'm developing it in Jupyterlab than it does when live as a model, but I don't want to manually edit a true/false variable every time. Is there a smart way to do this programmatically? 
Yes, here's a sample python snippet you can use to determine if you're in a model: 
import os
os.environ['HOSTNAME'].startswith('model')
Domino injects a handful of useful environment variables into your runs - you can use the `HOSTNAME` environment variable to tell if you're inside a model. 
In a Domino model, it will look like model-<hash>​, for example: 
HOSTNAME=model-5cw2d57d36e0fb0107a9c5c2-7b4574f7b9-htv2r 
In a Domino run, it will look like domino-run-<hash>, for example:
HOSTNAME=domino-run-5ce2be3d43e0sb0107a9c5a9
​
When running locally, it won't exist unless you've created it on your machine. 

 

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  • Jaclyn Patterson
    Here's a sample python snippet you can use to determine if you're in a model:
    <div>import os&nbsp;</div><div>
os.environ['HOSTNAME'].startswith('model')</div>
    Domino injects a handful of useful environment variables into your runs - you can use the `HOSTNAME` environment variable to tell if you're inside a model. 

    In a Domino model, it will look like model-<hash>​, for example: 
    HOSTNAME=model-5cw2d57d36e0fb0107a9c5c2-7b4574f7b9-htv2r 

    In a Domino run, it will look like domino-run-<hash>, for example:
    HOSTNAME=domino-run-5ce2be3d43e0sb0107a9c5a9
    ​
    When running locally, it won't exist unless you've created it on your machine. 

    Submitted by: mac.rogers

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